← C3×C3⋊((C3⋊D3)⋊A4) #14519266
Order 1944.
968 conjugacy classes of subgroups; only the 72 normal subgroups are shown.
This group has 968 conjugacy classes of subgroups — too many to draw. Only its 72 normal subgroups are shown.
Dotted edges: containments with no intermediate normal subgroup — omitted non-normal subgroups may lie between.
| subgroup | G/H | |
|---|---|---|
| center, hypercenter | C3 | C3⋊((C3⋊D3)⋊A4) |
| commutator, cosocle, hypocenter | C22×C33 | C2×C32 |
| Frattini | C3 | C3×A4×C3⋊D3 |
| Fitting | C22×C34 | C2×C3 |
| socle | C22×C33 | C3×D3 |
| LCS | G ▷ C22×C33 | |
| UCS | C1 ◁ C3 | |
Splittings G = N ⋊ H with N normal; H ≅ G/N.
| N | H ≅ G/N | type |
|---|---|---|
| 1. C32×C22⋊H(3,𝔽3) | C2 | semidirect |
| 2. C22×C3×C3⋊(C3⋊D3) | C3 | semidirect |
| 4. C3⋊((C3⋊D3)⋊A4) | C3 | direct (N × H) |
| 7. C22×C34 | C2×C3 | semidirect |
| 11. C33×A4 | D3 | semidirect |
| 15. C3×C22⋊H(3,𝔽3) | D3 | semidirect |
| 16. C3×C22⋊H(3,𝔽3) | C2×C3 | semidirect |
| 18. C22×C3⋊(C3⋊D3) | C32 | semidirect |
| 28. C3×C3⋊(C3⋊D3) | A4 | semidirect |
| 37. C22×C33 | C3×D3 | semidirect |
| 38. C22×C33 | C2×C32 | semidirect |
| 56. C32×A4 | C3×D3 | semidirect |
| 57. C32×A4 | C3⋊D3 | semidirect |
| 61. C22⋊H(3,𝔽3) | C3×D3 | semidirect |
| 64. C34 | C2×A4 | semidirect |
| 87. C3⋊(C3⋊D3) | C3×A4 | semidirect |
| 106. C22×C32 | (C3⋊D3)⋊C3 | semidirect |
| 108. C22×C32 | C32×D3 | semidirect |
| 134. C3×A4 | C3×C3⋊D3 | semidirect |
| 151. C33 | D3×A4 | semidirect |
| 152. C33 | C2×C3×A4 | semidirect |
| 195. C22×C3 | C3×(C3⋊D3)⋊C3 | semidirect |
| 196. C22×C3 | C3⋊((C3⋊D3)⋊C3) | semidirect |
| 228. C32 | (C3⋊D3)⋊A4 | semidirect |
| 230. C32 | C3×D3×A4 | semidirect |
| 251. C22 | C3×C3⋊((C3⋊D3)⋊C3) | semidirect |
| 259. C3 | C3×(C3⋊D3)⋊A4 | semidirect |
| 260. C3 | C3⋊((C3⋊D3)⋊A4) | direct (N × H) |
By isomorphism type — maximal subgroups of the same type appear once, whether or not they are normal.
| subgroup | index |
|---|---|
| C32×C22⋊H(3,𝔽3) | 2 |
| C22×C3×C3⋊(C3⋊D3) | 3 |
| C3×A4×C3⋊D3 | 3 |
| C3⋊((C3⋊D3)⋊A4) | 3 |
| C3×(C3⋊D3)⋊A4 | 3 |
| C3×C3⋊((C3⋊D3)⋊C3) | 4 |